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8a^2=26a-20
We move all terms to the left:
8a^2-(26a-20)=0
We get rid of parentheses
8a^2-26a+20=0
a = 8; b = -26; c = +20;
Δ = b2-4ac
Δ = -262-4·8·20
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-6}{2*8}=\frac{20}{16} =1+1/4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+6}{2*8}=\frac{32}{16} =2 $
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